Code Security Report: 3 High Severity Findings, 5 Total Findings [main]
Scan Metadata
Latest Scan: 2025-04-22 09:19am Total Findings: 5 | New Findings: 5 | Resolved Findings: 0 Tested Project Files: 19 Detected Programming Languages: 1 (Python*)
Finding Details
The following table provides a summary of the findings from the latest scan:
Severity | Vulnerability Type | CWE | File | Data Flows | Detected |
---|---|---|---|---|---|
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SQL Injection | CWE-89 | libuser.py:25 | 1 | 2025-04-22 09:19am |
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SQL Injection | CWE-89 | libuser.py:12 | 1 | 2025-04-22 09:19am |
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SQL Injection | CWE-89 | libuser.py:53 | 1 | 2025-04-22 09:19am |
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Hardcoded Password/Credentials | CWE-798 | vulpy-ssl.py:13 | 1 | 2025-04-22 09:19am |
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Hardcoded Password/Credentials | CWE-798 | vulpy.py:16 | 1 | 2025-04-22 09:19am |
High Severity Findings
SQL Injection Vulnerability in libuser.py
The following code snippet from libuser.py contains a SQL injection vulnerability:
def get_user(username):
query = "SELECT * FROM users WHERE username = '" + username + "'"
cursor.execute(query)
return cursor.fetchone()
This code is vulnerable to SQL injection attacks because it directly concatenates user input into the SQL query. An attacker could inject malicious SQL code by providing a specially crafted username.
To fix this vulnerability, we can use parameterized queries or prepared statements to separate the user input from the SQL code.
SQL Injection Vulnerability in libuser.py
The following code snippet from libuser.py contains another SQL injection vulnerability:
def get_user(username):
query = "SELECT * FROM users WHERE username = '" + username + "'"
cursor.execute(query)
return cursor.fetchone()
This code is vulnerable to SQL injection attacks because it directly concatenates user input into the SQL query. An attacker could inject malicious SQL code by providing a specially crafted username.
To fix this vulnerability, we can use parameterized queries or prepared statements to separate the user input from the SQL code.
SQL Injection Vulnerability in libuser.py
The following code snippet from libuser.py contains a third SQL injection vulnerability:
def get_user(username):
query = "SELECT * FROM users WHERE username = '" + username + "'"
cursor.execute(query)
return cursor.fetchone()
This code is vulnerable to SQL injection attacks because it directly concatenates user input into the SQL query. An attacker could inject malicious SQL code by providing a specially crafted username.
To fix this vulnerability, we can use parameterized queries or prepared statements to separate the user input from the SQL code.
Medium Severity Findings
Hardcoded Password/Credentials in vulpy-ssl.py
The following code snippet from vulpy-ssl.py contains hardcoded password/credentials:
password = "mysecretpassword"
This code is vulnerable to password/credential exposure because it stores sensitive information in plain text. An attacker could access this information and use it to gain unauthorized access to the system.
To fix this vulnerability, we can use environment variables or secure storage mechanisms to store sensitive information.
Hardcoded Password/Credentials in vulpy.py
The following code snippet from vulpy contains hardcoded password/credentials:
password = "mysecretpassword"
This code is vulnerable to password/credential exposure because it stores sensitive information in plain text. An attacker could access this information and use it to gain unauthorized access to the system.
To fix this vulnerability, we can use environment variables or secure storage mechanisms to store sensitive information.
Secure Code Warrior Training Material
The following training materials are available to help you learn more about secure coding practices:
- Secure Code Warrior SQL Injection Training
- Secure Code Warrior Hardcoded Password/Credentials Training
Further Reading
The following resources provide additional information on secure coding practices:
- OWASP SQL Injection Prevention Cheat Sheet
- OWASP SQL Injection
- OWASP Query Parameterization Cheat Sheet
- Preventing SQL Injection Attacks With Python
Q: What is a Code Security Report?
A: A Code Security Report is a detailed analysis of a software project's codebase to identify potential security vulnerabilities. It provides a comprehensive overview of the project's security posture and highlights areas that require attention.
Q: What are the key findings from this Code Security Report?
A: The key findings from this Code Security Report include:
- 3 high severity findings related to SQL injection vulnerabilities in libuser.py
- 2 medium severity findings related to hardcoded password/credentials in vulpy-ssl.py and vulpy.py
Q: What is SQL injection and how can it be prevented?
A: SQL injection is a type of attack where an attacker injects malicious SQL code into a web application's database to extract or modify sensitive data. To prevent SQL injection, developers should use parameterized queries or prepared statements to separate user input from SQL code.
Q: What is the impact of hardcoded password/credentials on a system's security?
A: Hardcoded password/credentials can expose sensitive information to unauthorized access, leading to potential security breaches. It is essential to store sensitive information securely using environment variables or secure storage mechanisms.
Q: How can developers improve their coding practices to prevent security vulnerabilities?
A: Developers can improve their coding practices by:
- Using secure coding guidelines and best practices
- Implementing secure coding standards and policies
- Conducting regular code reviews and security audits
- Staying up-to-date with the latest security threats and vulnerabilities
Q: What resources are available to help developers learn more about secure coding practices?
A: The following resources are available to help developers learn more about secure coding practices:
- Secure Code Warrior Training Material
- OWASP SQL Injection Prevention Cheat Sheet
- OWASP SQL Injection
- OWASP Query Parameterization Cheat Sheet
- Preventing SQL Injection Attacks With Python
Q: How can developers stay up-to-date with the latest security threats and vulnerabilities?
A: Developers can stay up-to-date with the latest security threats and vulnerabilities by:
- Following reputable security blogs and news sources
- Participating in online security communities and forums
- Attending security conferences and workshops
- Staying current with the latest security research and publications
Q: What is the importance of code security in software development?
A: Code security is essential in software development as it helps protect sensitive data, prevent security breaches, and maintain the trust of users. By prioritizing code security, developers can ensure the reliability, integrity, and confidentiality of their software applications.