Integral Of Sin(x) / Sin(3x), Looking For Another Solution

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A Novel Approach to Integrating sin(x) / sin(3x)

The integration of trigonometric functions is a fundamental concept in calculus, with numerous applications in physics, engineering, and other fields. One of the most challenging integrals in this category is sin(x) / sin(3x). While the typical solution involves rewriting sin(3x) as 3 sin(x) - 4 sin^3(x), canceling out sin(x), and then multiplying the numerator and denominator by sec^2(x), resulting in a logarithmic function with tan(x), we will explore an alternative approach to solving this integral.

The integral sin(x) / sin(3x) is a classic example of a trigonometric integral that can be solved using various techniques. The typical solution, as mentioned earlier, involves rewriting sin(3x) in terms of sin(x) and then simplifying the expression. However, this approach can be cumbersome and may not be immediately apparent to students or practitioners who are new to integration.

In this section, we will present an alternative approach to integrating sin(x) / sin(3x). Our method involves using the substitution method, specifically the tangent half-angle substitution. This technique is useful for integrating expressions that involve trigonometric functions of the form sin(ax) / sin(bx), where a and b are constants.

Step 1: Tangent Half-Angle Substitution

To begin, we will use the tangent half-angle substitution, which states that:

tan(x/2) = t

This implies that:

x = 2 arctan(t)

We will also need the following derivatives:

dx/dt = 2 / (1 + t^2)

Step 2: Express sin(x) and sin(3x) in Terms of t

Using the tangent half-angle substitution, we can express sin(x) and sin(3x) in terms of t as follows:

sin(x) = 2t / (1 + t^2)

sin(3x) = 3 sin(x) - 4 sin^3(x)

Substituting the expression for sin(x) into the equation for sin(3x), we get:

sin(3x) = 3(2t / (1 + t^2)) - 4(2t / (1 + t2))3

Simplifying this expression, we get:

sin(3x) = 6t / (1 + t^2) - 48t^3 / (1 + t2)3

Step 3: Substitute into the Integral

Now that we have expressed sin(x) and sin(3x) in terms of t, we can substitute these expressions into the original integral:

∫ sin(x) / sin(3x) dx

Substituting the expressions for sin(x) and sin(3x), we get:

∫ (2t / (1 + t^2)) / (6t / (1 + t^2) - 48t^3 / (1 + t2)3) dt

Step 4: Simplify the Integral

To simplify the integral, we can multiply the numerator and denominator by (1 + t2)3, which is the least common multiple of the denominators:

∫ (2t(1 + t2)3) / (6t(1 + t2)3 - 48t^3(1 + t2)3) dt

Simplifying the numerator and denominator, we get:

∫ (2t(1 + t2)3) / (6t(1 + t2)3 - 48t^3(1 + t2)3) dt

= ∫ (2t(1 + t2)3) / (6t(1 + t2)3 - 48t^3(1 + t2)3) dt

= ∫ (2t(1 + t2)3) / (6t(1 + t2)3 - 48t^3(1 + t2)3) dt

Step 5: Evaluate the Integral

To evaluate the integral, we can use the following substitution:

u = 1 + t^2

du/dt = 2t

Substituting this expression into the integral, we get:

∫ (2t(1 + t2)3) / (6t(1 + t2)3 - 48t^3(1 + t2)3) dt

= ∫ (2u^3) / (6u^3 - 48u^3) du

= ∫ (2u^3) / (-42u^3) du

= ∫ (-2/42) du

= -1/21 ∫ du

= -1/21 u + C

Substituting back u = 1 + t^2, we get:

-1/21 (1 + t^2) + C

In this article, we presented an alternative approach to integrating sin(x) / sin(3x). Our method involved using the tangent half-angle substitution, which allowed us to express sin(x) and sin(3x) in terms of t. We then substituted these expressions into the original integral and simplified the resulting expression. Finally, we evaluated the integral using the substitution method. This approach provides a novel solution to the integral sin(x) / sin(3x), which can be useful for students and practitioners who are new to integration.

  • [1] "Calculus" by Michael Spivak
  • [2] "Trigonometry" by I.M. Gelfand
  • [3] "Integration" by R. Courant
  • [1] "Tangent Half-Angle Substitution" by Wolfram MathWorld
  • [2] "Integration by Substitution" by Khan Academy
  • [3] "Trigonometric Integrals" by MIT OpenCourseWare
    Frequently Asked Questions (FAQs) about Integrating sin(x) / sin(3x)

A: The typical solution to the integral sin(x) / sin(3x) involves rewriting sin(3x) as 3 sin(x) - 4 sin^3(x), canceling out sin(x), and then multiplying the numerator and denominator by sec^2(x), resulting in a logarithmic function with tan(x).

A: The tangent half-angle substitution is useful for integrating sin(x) / sin(3x) because it allows us to express sin(x) and sin(3x) in terms of t, which simplifies the integral and makes it easier to evaluate.

A: The tangent half-angle substitution is a technique used in integration that involves substituting tan(x/2) = t, which implies that x = 2 arctan(t). This substitution is useful for integrating trigonometric functions of the form sin(ax) / sin(bx), where a and b are constants.

A: To apply the tangent half-angle substitution to the integral sin(x) / sin(3x), you need to express sin(x) and sin(3x) in terms of t using the substitution tan(x/2) = t. Then, substitute these expressions into the original integral and simplify the resulting expression.

A: The final answer to the integral sin(x) / sin(3x) is -1/21 (1 + t^2) + C, where C is the constant of integration.

A: Yes, the tangent half-angle substitution can be used to integrate other trigonometric functions of the form sin(ax) / sin(bx), where a and b are constants. However, the specific substitution and simplification steps may vary depending on the function being integrated.

A: Some common mistakes to avoid when using the tangent half-angle substitution include:

  • Not expressing sin(x) and sin(3x) in terms of t correctly
  • Not simplifying the resulting expression correctly
  • Not evaluating the integral correctly
  • Not checking the domain of the function being integrated

A: You can find more information about the tangent half-angle substitution and its applications in various calculus textbooks, online resources, and academic papers. Some recommended resources include:

  • "Calculus" by Michael Spivak
  • "Trigonometry" by I.M. Gelfand
  • "Integration" by R. Courant
  • "Tangent Half-Angle Substitution" by Wolfram MathWorld
  • "Integration by Substitution" by Khan Academy
  • "Trigonometric Integrals" by MIT OpenCourseWare